class="algoSlug_icon" data-priority="2">Web. class="algoSlug_icon" data-priority="2">Web. Two moles of an ideal **monoatomic** **gas** is expanded according to the equation P T = **constant** from its initial state P 0, V 0 to the final state due to which its **pressure** becomes half of the initial **pressure**. The change in internal energy is Important Points to Remember on Laws of Thermodynamics 1. Thermodynamics:. class="algoSlug_icon" data-priority="2">Web.

## mm

According to the first law of thermodynamics, for a **constant** volume process with a monatomic ideal **gas**, the molar specific heat will be: Cv = 3/2R = 12.5 J/mol K because U = 3/2nRT It can be derived that the molar specific heat at **constant** **pressure** is: Cp = Cv + R = 5/2R = 20.8 J/mol K. 20. A monatomic **gas** (ideal) is supplied 80 joule heatat **constant** **pressure**. The internal energy of gas,increase Get the answers you need, now! riya12367 riya12367 18.09.2019 ... W = - 64 J ( negative sign indicates **work** **done** is **by** the system) Now from Thermodynamic law, we get. Q = ΔE + W. ΔE = Q - W = 80 - (-64). The volume of 30.0 moles of a **monoatomic** ideal **gas** is reduced at a uniform rate from 0.616m 3 to 0.308m 3 in 2h. Its temperature is increased at a uniform rate from 27.0 C to 450 C. The **gas** passes through thermodynamic equilibrium states throughout. (a) Write down explicitly how the temperature and the volume of the **gas** depend on time (in hours). Answer (1 of 3): **Pressure** times displacement. Pure and simple. To elaborate the linguistic aspect of this, I am afraid I am going to rant now, so you can stop reading here if I am boringly off topic..

## zw

The **work** **done** in adiabatic compression of 2 mole of an ideal **monoatomic** **gas** by **constant** external **pressure** of 2 atm starting from initial **pressure** of 1 atm and initial temperature of 300 K is:Take R =2 cal / K . mol A. 720 calB. 800 calC. 550 calD. 360 cal. Two moles of a **monatomic** ideal **gas** such as helium is compressed adiabatically and reversibly from a state (3 atm, 5 L) to a state with **pressure** 4 atm. (a) Find the volume and temperature of the final state. (b) Find the temperature of the initial state of the **gas**. (c) Find the **work** **done** by the **gas** in the process.. One mole of a **monoatomic** perfect **gas** initially at temperature T0 expands from volume V0 to 2V0 (a) at **constant** temperature (b) at **constant** **pressure**. Calculate **work** of expansion and heat absorbed in each case. 2 Answer (s) Answer Now. 0 Likes. It is given that an ideal monatomic **gas** undergoes a process where its **pressure** is inversely proportional to its temperatureP1TPTconstant Ideal **gas** equationPVnRTTPV.

## pw

class="algoSlug_icon" data-priority="2">Web. Nov 12, 2011 · If 650 J of heat are added to 21 moles of a **monatomic gas at constant pressure**, how much does the temperature of the **gas** increase? (in Kelvins) Homework Equations U = nRT Careful. For a **monatomic** ideal **gas**, internal energy, U = 3nRT/2 Q= (5/2)nR (T2-T1) Note that T is in Kelvins, and Q is in Joules and R is in Joule/mol Kelvin..

## yl

Step 1: Given that: The heat supplied to the **monoatomic** **gas**= Q Heat is supplied at **constant** **pressure**. Step 2: Calculation of **work** **done**: According to first law of thermodynamics Q= ΔU +W Where ΔU is the change in internal energy and W is the amount of **work** **done**. Thus, W = Q−ΔU The internal energy of a **gas** is given **by**; ΔU = nCV ΔT. Two moles of a monatomic ideal **gas** such as helium is compressed adiabatically and reversibly from a state (3 atm, 5 L) to a state with **pressure** 4 atm. (a) Find the volume and temperature of the final state. (b) Find the temperature of the initial state of the **gas**. (c) Find the **work** **done** **by** the **gas** in the process. A **monoatomic** **gas** expands at a **constant** **pressure** on heating. The percentage of heat supplied that increases the internal energy of the **gas** and that is involved in the expansion is Medium. Answer to Solved A **monatomic** ideal **gas** expands **at constant** **pressure** of ... **gas** expands **at constant** **pressure** of 86 kPa from 1.1 mºto 4.2 m3. Calculate the **work** **done** ....

## qz

class="algoSlug_icon" data-priority="2">Web. A **monoatomic** **gas** is supplied heat Q very slowly keeping the **pressure** **constant**. The **work** **done** **by** the **gas** is A 52Q B 53Q C 5Q D 32Q Medium Solution Verified by Toppr Correct option is A) Q U= 53,or U= 53Q From the first law of thermodynamics Q= U+W W= 52Q Solve any question of Thermodynamics with:- Patterns of problems > Was this answer helpful? 0 0. If the **gas** expands against the piston, it exerts a force through a distance and does **work** on the piston. If the piston compresses the **gas** as it is moved inward, **work** is also **done**—in this case, on the **gas**. The **work** associated with such volume changes can be determined as follows: Let the **gas** **pressure** on the piston face be p.. class="algoSlug_icon" data-priority="2">Web.

## eu

class="algoSlug_icon" data-priority="2">Web. role="button" aria-expanded="false">. Two moles of a monatomic ideal **gas** such as helium is compressed adiabatically and reversibly from a state (3 atm, 5 L) to a state with **pressure** 4 atm. (a) Find the volume and temperature of the final state. (b) Find the temperature of the initial state of the **gas**. (c) Find the **work** **done** **by** the **gas** in the process.

## cl

class="algoSlug_icon" data-priority="2">Web. **Constant** Volume. Heat or the transfer of energy has the potential to cause two things: increase the temperature (Q) Perform **Work** (W) **Work** is W= (Force) (displacement).it causes enclosed spaces to expand or push away hence the displacement part. Therefore the total change in energy is this equation Delta E = Q (heat to change temp) + W (**work**). Monatomic ideal **gas** takes up Q heat, while its volume increases but the **pressure** stays the same. How many %s of the heat is for expansion **work**? ... Using the convention that $\Delta W$ is the **work** **done** **by** the system, 1st law of thermodynamics states: $$\Delta Q=\Delta U+\Delta \tag{1}W$$ Now, for ideal **gas** undergoing isobaric process:.

## fz

The volume of 30.0 moles of a **monoatomic** ideal **gas** is reduced at a uniform rate from 0.616m 3 to 0.308m 3 in 2h. Its temperature is increased at a uniform rate from 27.0 C to 450 C. The **gas** passes through thermodynamic equilibrium states throughout. (a) Write down explicitly how the temperature and the volume of the **gas** depend on time (in hours). questions and answers. b how much **work** is **done** on the **gas** in this process a mole of **monatomic**. Question. Heat Transfer. (b) How much **work** is **done** on the **gas** in this process? A mole of **monatomic** ideal **gas** at 1 bar and 298.5 K is allowed to expand adiabatically against a **constant** **pressure** at 0.798 bar until equilibrium is reached.. According to the first law of thermodynamics, for a **constant** volume process with a monatomic ideal **gas**, the molar specific heat will be: Cv = 3/2R = 12.5 J/mol K because U = 3/2nRT It can be derived that the molar specific heat at **constant** **pressure** is: Cp = Cv + R = 5/2R = 20.8 J/mol K. The molar specific heat of a **gas** **at** **constant** **pressure** (Cp is the amount of heat required to raise the temperature of 1 mol of the **gas** **by** 1 C at the **constant** **pressure**. Its value for monatomic ideal **gas** is 5R/2 and the value for diatomic ideal **gas** is 7R/2. May 13, 2021 · If we then remove the weights, holding a **constant** volume, we proceed on to State 2. The **work** **done** in this process is shown by the yellow shaded area. Using either process we change the state of the **gas** from State 1 to State 2. But the **work** for the **constant** **pressure** process is greater than the **work** for the curved line process.. **Pressure**-volume **work**: **Work** **done** by a **gas** Gases can do **work** through expansion or compression against a **constant** external **pressure**. **Work** **done** by gases is also sometimes called **pressure**-volume or PV **work** for reasons that will hopefully become more clear in this section! Let's consider **gas** contained in a piston. [Wait, what is a piston??].

## cr

What is the **work** **done** by an ideal **monatomic** **gas** at a **pressure** of 3×10^5N/m2 and a temperature of 300 K undergoes a quasi-static isobaric expansion from 2.0 × 103 to 4.0 × 103 2.5×10^(3) to 4×10^(3) cm^(3).. monatomic **gas** **at** **constant** volume and expanding/compressing the **gas** isothermally to twice its original volume. (e) Sketch the cycle on a p-V (**pressure**-volume) diagram. [ 3 ] (f) How much heat is absorbed in the first stage during which the **gas** is heated at **constant** volume? [ 3 ]. class="algoSlug_icon" data-priority="2">Web.

## rk

We also know that the molar specific heat at **constant** **pressure** is given by the equation, C p = ( f 2 + 1) R Therefore for the given monatomic **gas**, we get ⇒ C p = ( 3 2 + 1) R ⇒ C p = 5 2 R By substituting this in the equation for change in heat energy, we get ⇒ Δ Q = n × 5 2 R Δ T ⇒ Δ Q = 5 2 n R Δ T. class="algoSlug_icon" data-priority="2">Web. Answer: The oxygen **gas** **at** 34.5°C expands from 45.7L to 74.5L against a **constant** **pressure** of 1 bar. What is the **work** **done** in joules? P = 1 bar = 1 × 10⁵ N/m² ΔV = [(74.5 - 45.7) L] × (1 m³ / 1,000 L) = 0.0288 m³ **Work** **done** = P ΔV = (1 × 10⁵ N/m²) × (0.0288 m³) = 2,880 J.

## xt

**Constant** **Pressure** Process If p = const., then dp = 0, and, from 1, p dV = R dT; i.e., the **work** **done** by the **gas** in expanding through the differential volume dV is directly proportional to the temperature change dT. If the **gas** has a specific heat **at constant** **pressure** of C p, then dq = C p dT, and, from 2 (with 3 ), C p dT = C V dT + R dT. class="algoSlug_icon" data-priority="2">Web. Nov 12, 2022 · For a **monoatomic** **gas**, the **work** **done** **at ****constant** **pressure** is W. The heat supplied **at constant** volume for the same rise in ... (2) 3W/2 (3) 5W/2 (4) W.

## xu

Dec 31, 2018 · A **monatomic** **gas** expands **at constant** **pressure** on heating. The percentage of heat **supplied that increases the internal** energy of the **gas** and that is inv asked May 29, 2019 in Physics by JayantChakraborty ( 78.8k points). class="algoSlug_icon" data-priority="2">Web. **Pressure**-volume **work**: **Work** **done** by a **gas** Gases can do **work** through expansion or compression against a **constant** external **pressure**. **Work** **done** by gases is also sometimes called **pressure**-volume or PV **work** for reasons that will hopefully become more clear in this section! Let's consider **gas** contained in a piston. [Wait, what is a piston??].

## ak

class="algoSlug_icon" data-priority="2">Web. . class="algoSlug_icon" data-priority="2">Web.

## rw

Answer to Solved A monatomic ideal **gas** expands at **constant** **pressure** of. class="algoSlug_icon" data-priority="2">Web. Solution For For a **monoatomic** **gas**, **work** **done** **at constant** **pressure** is W. The heat supplied **at constant** volume for the same rise in temperature of the g For a **monoatomic** **gas**, **work** **done** **at constant** **pressure** is W.. May 13, 2021 · If we then remove the weights, holding a **constant** volume, we proceed on to State 2. The **work** **done** in this process is shown by the yellow shaded area. Using either process we change the state of the **gas** from State 1 to State 2. But the **work** for the **constant** **pressure** process is greater than the **work** for the curved line process.. class="algoSlug_icon" data-priority="2">Web.

## yc

Physics Question **An ideal monatomic gas at a pressure** of 2.0 \times 10 ^ { 5 } \mathrm { N } / \mathrm { m } ^ { 2 } 2.0×105N/m2 and a temperature of 300 K undergoes a quasi-static isobaric expansion from 2.0 \times 10 ^ { 3 } \text { to } 4.0 \times 10 ^ { 3 } \mathrm { cm } ^ { 3 } 2.0×103 to 4.0×103cm3. (a) What is the **work** **done** by the **gas**?. What is the **work** **done** by an ideal **monatomic** **gas** at a **pressure** of 3×10^5N/m2 and a temperature of 300 K undergoes a quasi-static isobaric expansion from 2.0 × 103 to 4.0 × 103 2.5×10^(3) to 4×10^(3) cm^(3).. class="algoSlug_icon" data-priority="2">Web. The volume of 30.0 moles of a **monoatomic** ideal **gas** is reduced at a uniform rate from 0.616m 3 to 0.308m 3 in 2h. Its temperature is increased at a uniform rate from 27.0 C to 450 C. The **gas** passes through thermodynamic equilibrium states throughout. (a) Write down explicitly how the temperature and the volume of the **gas** depend on time (in hours).

## lf

**Pressure**-volume **work**: **Work** **done** by a **gas** Gases can do **work** through expansion or compression against a **constant** external **pressure**. **Work** **done** by gases is also sometimes called **pressure**-volume or PV **work** for reasons that will hopefully become more clear in this section! Let's consider **gas** contained in a piston. [Wait, what is a piston??]. Answer to Solved A **monatomic** ideal **gas** expands **at constant** **pressure** of ... **gas** expands **at constant** **pressure** of 86 kPa from 1.1 mºto 4.2 m3. Calculate the **work** **done** ....

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