# Work done by monoatomic gas at constant pressure td

class="algoSlug_icon" data-priority="2">Web. class="algoSlug_icon" data-priority="2">Web. Two moles of an ideal monoatomic gas is expanded according to the equation P T = constant from its initial state P 0, V 0 to the final state due to which its pressure becomes half of the initial pressure. The change in internal energy is Important Points to Remember on Laws of Thermodynamics 1. Thermodynamics:. class="algoSlug_icon" data-priority="2">Web.

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According to the first law of thermodynamics, for a constant volume process with a monatomic ideal gas, the molar specific heat will be: Cv = 3/2R = 12.5 J/mol K because U = 3/2nRT It can be derived that the molar specific heat at constant pressure is: Cp = Cv + R = 5/2R = 20.8 J/mol K. 20. A monatomic gas (ideal) is supplied 80 joule heatat constant pressure. The internal energy of gas,increase Get the answers you need, now! riya12367 riya12367 18.09.2019 ... W = - 64 J ( negative sign indicates work done is by the system) Now from Thermodynamic law, we get. Q = ΔE + W. ΔE = Q - W = 80 - (-64). The volume of 30.0 moles of a monoatomic ideal gas is reduced at a uniform rate from 0.616m 3 to 0.308m 3 in 2h. Its temperature is increased at a uniform rate from 27.0 C to 450 C. The gas passes through thermodynamic equilibrium states throughout. (a) Write down explicitly how the temperature and the volume of the gas depend on time (in hours). Answer (1 of 3): Pressure times displacement. Pure and simple. To elaborate the linguistic aspect of this, I am afraid I am going to rant now, so you can stop reading here if I am boringly off topic..

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The work done in adiabatic compression of 2 mole of an ideal monoatomic gas by constant external pressure of 2 atm starting from initial pressure of 1 atm and initial temperature of 300 K is:Take R =2 cal / K . mol A. 720 calB. 800 calC. 550 calD. 360 cal. Two moles of a monatomic ideal gas such as helium is compressed adiabatically and reversibly from a state (3 atm, 5 L) to a state with pressure 4 atm. (a) Find the volume and temperature of the final state. (b) Find the temperature of the initial state of the gas. (c) Find the work done by the gas in the process.. One mole of a monoatomic perfect gas initially at temperature T0 expands from volume V0 to 2V0 (a) at constant temperature (b) at constant pressure. Calculate work of expansion and heat absorbed in each case. 2 Answer (s) Answer Now. 0 Likes. It is given that an ideal monatomic gas undergoes a process where its pressure is inversely proportional to its temperatureP1TPTconstant Ideal gas equationPVnRTTPV.

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Step 1: Given that: The heat supplied to the monoatomic gas= Q Heat is supplied at constant pressure. Step 2: Calculation of work done: According to first law of thermodynamics Q= ΔU +W Where ΔU is the change in internal energy and W is the amount of work done. Thus, W = Q−ΔU The internal energy of a gas is given by; ΔU = nCV ΔT. Two moles of a monatomic ideal gas such as helium is compressed adiabatically and reversibly from a state (3 atm, 5 L) to a state with pressure 4 atm. (a) Find the volume and temperature of the final state. (b) Find the temperature of the initial state of the gas. (c) Find the work done by the gas in the process. A monoatomic gas expands at a constant pressure on heating. The percentage of heat supplied that increases the internal energy of the gas and that is involved in the expansion is Medium. Answer to Solved A monatomic ideal gas expands at constant pressure of ... gas expands at constant pressure of 86 kPa from 1.1 mºto 4.2 m3. Calculate the work done ....

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class="algoSlug_icon" data-priority="2">Web. A monoatomic gas is supplied heat Q very slowly keeping the pressure constant. The work done by the gas is A 52Q B 53Q C 5Q D 32Q Medium Solution Verified by Toppr Correct option is A) Q U= 53,or U= 53Q From the first law of thermodynamics Q= U+W W= 52Q Solve any question of Thermodynamics with:- Patterns of problems > Was this answer helpful? 0 0. If the gas expands against the piston, it exerts a force through a distance and does work on the piston. If the piston compresses the gas as it is moved inward, work is also done—in this case, on the gas. The work associated with such volume changes can be determined as follows: Let the gas pressure on the piston face be p.. class="algoSlug_icon" data-priority="2">Web.

## eu

class="algoSlug_icon" data-priority="2">Web. role="button" aria-expanded="false">. Two moles of a monatomic ideal gas such as helium is compressed adiabatically and reversibly from a state (3 atm, 5 L) to a state with pressure 4 atm. (a) Find the volume and temperature of the final state. (b) Find the temperature of the initial state of the gas. (c) Find the work done by the gas in the process.

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class="algoSlug_icon" data-priority="2">Web. Constant Volume. Heat or the transfer of energy has the potential to cause two things: increase the temperature (Q) Perform Work (W) Work is W= (Force) (displacement).it causes enclosed spaces to expand or push away hence the displacement part. Therefore the total change in energy is this equation Delta E = Q (heat to change temp) + W (work). Monatomic ideal gas takes up Q heat, while its volume increases but the pressure stays the same. How many %s of the heat is for expansion work? ... Using the convention that $\Delta W$ is the work done by the system, 1st law of thermodynamics states: $$\Delta Q=\Delta U+\Delta \tag{1}W$$ Now, for ideal gas undergoing isobaric process:.

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The volume of 30.0 moles of a monoatomic ideal gas is reduced at a uniform rate from 0.616m 3 to 0.308m 3 in 2h. Its temperature is increased at a uniform rate from 27.0 C to 450 C. The gas passes through thermodynamic equilibrium states throughout. (a) Write down explicitly how the temperature and the volume of the gas depend on time (in hours). questions and answers. b how much work is done on the gas in this process a mole of monatomic. Question. Heat Transfer. (b) How much work is done on the gas in this process? A mole of monatomic ideal gas at 1 bar and 298.5 K is allowed to expand adiabatically against a constant pressure at 0.798 bar until equilibrium is reached.. According to the first law of thermodynamics, for a constant volume process with a monatomic ideal gas, the molar specific heat will be: Cv = 3/2R = 12.5 J/mol K because U = 3/2nRT It can be derived that the molar specific heat at constant pressure is: Cp = Cv + R = 5/2R = 20.8 J/mol K. The molar specific heat of a gas at constant pressure (Cp is the amount of heat required to raise the temperature of 1 mol of the gas by 1 C at the constant pressure. Its value for monatomic ideal gas is 5R/2 and the value for diatomic ideal gas is 7R/2. May 13, 2021 · If we then remove the weights, holding a constant volume, we proceed on to State 2. The work done in this process is shown by the yellow shaded area. Using either process we change the state of the gas from State 1 to State 2. But the work for the constant pressure process is greater than the work for the curved line process.. Pressure-volume work: Work done by a gas Gases can do work through expansion or compression against a constant external pressure. Work done by gases is also sometimes called pressure-volume or PV work for reasons that will hopefully become more clear in this section! Let's consider gas contained in a piston. [Wait, what is a piston??].

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What is the work done by an ideal monatomic gas at a pressure of 3×10^5N/m2 and a temperature of 300 K undergoes a quasi-static isobaric expansion from 2.0 × 103 to 4.0 × 103 2.5×10^(3) to 4×10^(3) cm^(3).. monatomic gas at constant volume and expanding/compressing the gas isothermally to twice its original volume. (e) Sketch the cycle on a p-V (pressure-volume) diagram. [ 3 ] (f) How much heat is absorbed in the first stage during which the gas is heated at constant volume? [ 3 ]. class="algoSlug_icon" data-priority="2">Web.

## rk

We also know that the molar specific heat at constant pressure is given by the equation, C p = ( f 2 + 1) R Therefore for the given monatomic gas, we get ⇒ C p = ( 3 2 + 1) R ⇒ C p = 5 2 R By substituting this in the equation for change in heat energy, we get ⇒ Δ Q = n × 5 2 R Δ T ⇒ Δ Q = 5 2 n R Δ T. class="algoSlug_icon" data-priority="2">Web. Answer: The oxygen gas at 34.5°C expands from 45.7L to 74.5L against a constant pressure of 1 bar. What is the work done in joules? P = 1 bar = 1 × 10⁵ N/m² ΔV = [(74.5 - 45.7) L] × (1 m³ / 1,000 L) = 0.0288 m³ Work done = P ΔV = (1 × 10⁵ N/m²) × (0.0288 m³) = 2,880 J.

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Constant Pressure Process If p = const., then dp = 0, and, from 1, p dV = R dT; i.e., the work done by the gas in expanding through the differential volume dV is directly proportional to the temperature change dT. If the gas has a specific heat at constant pressure of C p, then dq = C p dT, and, from 2 (with 3 ), C p dT = C V dT + R dT. class="algoSlug_icon" data-priority="2">Web. Nov 12, 2022 · For a monoatomic gas, the work done at constant pressure is W. The heat supplied at constant volume for the same rise in ... (2) 3W/2 (3) 5W/2 (4) W.

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Dec 31, 2018 · A monatomic gas expands at constant pressure on heating. The percentage of heat supplied that increases the internal energy of the gas and that is inv asked May 29, 2019 in Physics by JayantChakraborty ( 78.8k points). class="algoSlug_icon" data-priority="2">Web. Pressure-volume work: Work done by a gas Gases can do work through expansion or compression against a constant external pressure. Work done by gases is also sometimes called pressure-volume or PV work for reasons that will hopefully become more clear in this section! Let's consider gas contained in a piston. [Wait, what is a piston??].

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## rw

Answer to Solved A monatomic ideal gas expands at constant pressure of. class="algoSlug_icon" data-priority="2">Web. Solution For For a monoatomic gas, work done at constant pressure is W. The heat supplied at constant volume for the same rise in temperature of the g For a monoatomic gas, work done at constant pressure is W.. May 13, 2021 · If we then remove the weights, holding a constant volume, we proceed on to State 2. The work done in this process is shown by the yellow shaded area. Using either process we change the state of the gas from State 1 to State 2. But the work for the constant pressure process is greater than the work for the curved line process.. class="algoSlug_icon" data-priority="2">Web.

## yc

Physics Question An ideal monatomic gas at a pressure of 2.0 \times 10 ^ { 5 } \mathrm { N } / \mathrm { m } ^ { 2 } 2.0×105N/m2 and a temperature of 300 K undergoes a quasi-static isobaric expansion from 2.0 \times 10 ^ { 3 } \text { to } 4.0 \times 10 ^ { 3 } \mathrm { cm } ^ { 3 } 2.0×103 to 4.0×103cm3. (a) What is the work done by the gas?. What is the work done by an ideal monatomic gas at a pressure of 3×10^5N/m2 and a temperature of 300 K undergoes a quasi-static isobaric expansion from 2.0 × 103 to 4.0 × 103 2.5×10^(3) to 4×10^(3) cm^(3).. class="algoSlug_icon" data-priority="2">Web. The volume of 30.0 moles of a monoatomic ideal gas is reduced at a uniform rate from 0.616m 3 to 0.308m 3 in 2h. Its temperature is increased at a uniform rate from 27.0 C to 450 C. The gas passes through thermodynamic equilibrium states throughout. (a) Write down explicitly how the temperature and the volume of the gas depend on time (in hours).

## lf

Pressure-volume work: Work done by a gas Gases can do work through expansion or compression against a constant external pressure. Work done by gases is also sometimes called pressure-volume or PV work for reasons that will hopefully become more clear in this section! Let's consider gas contained in a piston. [Wait, what is a piston??]. Answer to Solved A monatomic ideal gas expands at constant pressure of ... gas expands at constant pressure of 86 kPa from 1.1 mºto 4.2 m3. Calculate the work done ....

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